document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=735016>Question 735016</A>: <I><SPAN STYLE=\"word-break: break-all;\"> log4(x+5)=3+log4(x+2)<BR>\n" );
document.write( "solve the logarithmic eqaution. be sure to reject any value that is not in the domain of the orginal logarithmic expressions </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #449259 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=449259\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log4(x+5)=3+log4(x+2)<P><BR>\n" );
document.write( "log4(x+5) - log4(x+2) = <P><BR>\n" );
document.write( "Remember that log(x) - log(y) = log(x/y) and logx(y)=a means x^a = y<P><BR>\n" );
document.write( "log4((x+5)/(x+2)) = 3<P><BR>\n" );
document.write( "4^3 = x+5/x+2<P><BR>\n" );
document.write( "64 = x+5/x+2<P><BR>\n" );
document.write( "64x + 128 = x+5<P><BR>\n" );
document.write( "63x = -123<P><BR>\n" );
document.write( "x = -123/63 = approximately 1.9524<BR>\n" );
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