document.write( "Question 735007: Perfect Square Trinomial\r
\n" ); document.write( "\n" ); document.write( "m^2 + m + 1/4\r
\n" ); document.write( "\n" ); document.write( "I tried but my teacher never explained how to do one with a fraction! Please Help!
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Algebra.Com's Answer #449243 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
You are trying to find (m+c)(m+c) so that the constant term is 1/4 and this must be \"c%5E2=1%2F4\". This would mean, \"c=1%2F2\". The question next is, will c=1/2 give you the m term that you need? \r
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\n" ); document.write( "\n" ); document.write( "You see, you want this: \"%28m%2Bc%29%28m%2Bc%29=m%5E2%2Bmc+%2Bmc%2Bc%5E2\"
\n" ); document.write( "and \"m%5E2%2Bmc%2Bmc%2Bc%5E2=m%5E2%2B1%2Am%2B1%2F4\".\r
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\n" ); document.write( "\n" ); document.write( "You must have both, \"2mc=m\" AND \"c%5E2=1%2F4%7D.++How+will+this+work%3F%0D%0AThe+2mc+means+that+%7B%7B%7B2c=1\". The c^2 as from before means \"c=1%2F2\". Using the 2c=1 result, solve for c and find \"c=1%2F2\". \r
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\n" ); document.write( "\n" ); document.write( "There it is. \"c=1%2F2\".
\n" ); document.write( "\"m%5E2%2Bm%2B1%2F4=%28m%2B1%2F2%29%5E2\".
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