document.write( "Question 734948: I need to find the slant asymptotes of \r
\n" ); document.write( "\n" ); document.write( "a. x^3+x^2/x^2-4
\n" ); document.write( "b. 2x^2+10x-12/x^2+x-6\r
\n" ); document.write( "\n" ); document.write( "I understand how to find the Vertical and Horizontal, but I'm confused on the slant portion. Please help! thank you!!!
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Algebra.Com's Answer #449211 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
to find the slant asymptotes of\r
\n" ); document.write( "\n" ); document.write( "a. \"%28x%5E3%2Bx%5E2%29%2F%28x%5E2-4%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%28x%2B1%29%2F%28x%5E2-2%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%28x%2B1%29%2F%28%28x-2%29%28x%2B2%29%29\"\r
\n" ); document.write( "\n" ); document.write( "The vertical asymptotes (and any restrictions on the domain) come from the zeroes of the denominator, so I'll set the denominator equal to zero and solve.\r
\n" ); document.write( "\n" ); document.write( "\"%28%28x-2%29%28x%2B2%29%29=0\"\r
\n" ); document.write( "\n" ); document.write( "if \"x-2=0\"...=>...\"x=2\"
\n" ); document.write( "if \"x%2B2=0\"...=>...\"x=-2\"\r
\n" ); document.write( "\n" ); document.write( "Then the domain is all \"x-values\" other than ± \"2\", and the two vertical asymptotes are at
\n" ); document.write( "\"x+=+2\" and \"x=-2\".\r
\n" ); document.write( "\n" ); document.write( "Since the degree is greater in the denominator than in the numerator, the \"y-values\" will be dragged down to the \"x-axis\", and the horizontal asymptote is therefore \"\"y+=+0\"\" (the \"x-axis\") .\r
\n" ); document.write( "\n" ); document.write( "The slant asymptote: use the long division to find it\r
\n" ); document.write( "\n" ); document.write( "----------\"x%2B1\"
\n" ); document.write( "--------|\"x%5E3%2Bx%5E2\"
\n" ); document.write( "\"x%5E2-4\")..\"x%5E3-4x\"
\n" ); document.write( "_________________
\n" ); document.write( "----------\"0%2B4x%2Bx%5E2\"
\n" ); document.write( "------------ \"x%5E2-4\"
\n" ); document.write( "________________
\n" ); document.write( "---------------\"4x%2B4\"\r
\n" ); document.write( "\n" ); document.write( "---------------\"4%28x%2B1%29\"\r
\n" ); document.write( "\n" ); document.write( "so, since \"x%2B1\" is a factor of the numerator\r
\n" ); document.write( "\n" ); document.write( "the slant asymptote: \"y+=+x+%2B+1\"\r
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\n" ); document.write( "\n" ); document.write( "b. \"%282x%5E2%2B10x-12%29%2F%28x%5E2%2Bx-6%29\"\r
\n" ); document.write( "\n" ); document.write( "horizontal asymptote: -> to \"-12%2F-6=2\" as \"x\"-> \"infinity\" or \"-infinity\"\r
\n" ); document.write( "\n" ); document.write( "so,horizontal asymptote is \"y=2\"\r
\n" ); document.write( "\n" ); document.write( "continue factoring\r
\n" ); document.write( "\n" ); document.write( "\"%282x%5E2%2B10x-12%29%2F%28x%5E2%2Bx-6%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"2%28x%5E2%2B5x-6%29%2F%28x%5E2%2Bx-6%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"2%28x%5E2-x%2B6x-6%29%2F%28x%5E2%2B3x-2x-6%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"2%28%28x%5E2-x%29%2B%286x-6%29%29%2F%28%28x%5E2%2B3x%29-%282x%2B6%29%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"2%28x%28x-1%29%2B6%28x-1%29%29%2F%28x%28x%2B3%29-2%28x%2B3%29%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"2%28%28x%2B6%29%28x-1%29%29%2F%28%28x-2%29%28x%2B3%29%29+\"\r
\n" ); document.write( "\n" ); document.write( "find values that make denominator equal to zero:\r
\n" ); document.write( "\n" ); document.write( "if\"x-2=0+\"....->...\"x=2\"\r
\n" ); document.write( "\n" ); document.write( "if\"x%2B3=0+\"....->...\"x=-3\"\r
\n" ); document.write( "\n" ); document.write( "these are vertical asymptotes\r
\n" ); document.write( "\n" ); document.write( "-there is no slant asymptote in this case\r
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