document.write( "Question 734890: I can't get the answer to the following problem ; \r
\n" ); document.write( "\n" ); document.write( "y-5x=-2
\n" ); document.write( "3x-7y=22\r
\n" ); document.write( "\n" ); document.write( "The instructions say to use the substitution method.
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Algebra.Com's Answer #449174 by KMST(5328)\"\" \"About 
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Substitution means that your first step is solving for one variable in one of the equations. For example
\n" ); document.write( "\"y-5x=-2\" --> \"y=5x-2\"
\n" ); document.write( "Note: Look for a variable that has no visible coefficient. In this case, the coefficient of \"y\" in \"y-5x=-2\" is an invisible number 1.
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\n" ); document.write( "The second step when using substitution is to substitute the expression found for the variable in the other equation.
\n" ); document.write( "In this case, since we found that \"y=5x-2\", we write (5x-2) instead of \"y\" in \"3x-7y=22\" to get
\n" ); document.write( "\"3x-7%285x-2%29=22\"
\n" ); document.write( "No we use the distributive property to transform that into
\n" ); document.write( "\"3x-7%2A%285x%29-7%2A%28-2%29=22\" and simplify to \"3x-35x%2B14=22\" and \"-32x%2B14=22\"
\n" ); document.write( "Then we solve \"-32x%2B14=22\"
\n" ); document.write( "\"-32x%2B14=22\" --> \"-32x=22%7D-14%7D%7D+--%3E+%7B%7B%7B-32x=8\" --> \"x=8%2F%28-32%29\" --> \"highlight%28x=-1%2F4%29\"
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\n" ); document.write( "As a final step, we substitute \"-1%2F4\" for \"x\" somewhere to find \"y\".
\n" ); document.write( "It may be easiest to use \"y=5x-2\". Substituting we get
\n" ); document.write( "\"y=5%28-1%2F4%29-2\"--> \"y=-5%2F4-2\" --> \"y=-5%2F4-8%2F4\" --> \"highlight%28y=-13%2F4%29\"
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\n" ); document.write( "NOTE: If you cannot find a variable with no visible coefficient, substitution will get cumbersome, as you would be working with fractions a lot. In that case, it is better to use a different method.
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