document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=734894>Question 734894</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How can I find the variable of -3e^(7a+9)+6=-6<BR>\n" );
document.write( "I need guidance for the steps I subtracted 6 and then<BR>\n" );
document.write( "I thought about moving the e in front of the 3 to make<BR>\n" );
document.write( "it a natural log but it didn't work out that way because<BR>\n" );
document.write( "you cant take the natural log of negative number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #449171 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=449171\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> subtracting 6 from both sides, you have\r<BR>\n" );
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document.write( "-3e^(7a+9) = -12\r<BR>\n" );
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document.write( "then divide by -3 and you get\r<BR>\n" );
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document.write( "e^(7a+9) = 4\r<BR>\n" );
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document.write( "take the natural log (ln) of both sides\r<BR>\n" );
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document.write( "ln(e^(7a+9)) = ln 4\r<BR>\n" );
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document.write( "bring down the exponent of e and we get\r<BR>\n" );
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document.write( "(7a+9)ln(e) = ln 4\r<BR>\n" );
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document.write( "note that the ln(e) is 1, so we have\r<BR>\n" );
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document.write( "7a+9 = ln(4) and\r<BR>\n" );
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document.write( "a = (ln(4) - 9) / 7 = -1.09 </SPAN>\n" );
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