document.write( "Question 734898: How do I completely factor the polynomial:
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Algebra.Com's Answer #449169 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"8x%5E3%2B64x%5E2%2B8x%2B64\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"%288x%5E3%2B64x%5E2%29%2B%288x%2B64%29\" Group the terms in two pairs\r
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\n" ); document.write( "\n" ); document.write( "\"8x%5E2%28x%2B8%29%2B8%28x%2B8%29\" Factor out the GCF \"8x%5E2\" out of the first group. Factor out the GCF \"8\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%288x%5E2%2B8%29%28x%2B8%29\" Since we have the common term \"x%2B8\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So \"8x%5E3%2B64x%5E2%2B8x%2B64\" factors to \"%288x%5E2%2B8%29%28x%2B8%29\"\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"8x%5E3%2B64x%5E2%2B8x%2B64=%288x%5E2%2B8%29%28x%2B8%29\"
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