document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=734837>Question 734837</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve log3(x-3) + log3(x+2) = log3 6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #449146 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=449146\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> note that all log bases are the same (namely 3), so we have\r<BR>\n" );
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document.write( "x-3 + x+2 = 6\r<BR>\n" );
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document.write( "2x - 1 = 6   and\r<BR>\n" );
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document.write( "2x = 7 and x = 3.5 </SPAN>\n" );
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