document.write( "Question 734781: log x + log 4 =1 please help with this\r
\n" ); document.write( "\n" ); document.write( "log x - log 9 =3\r
\n" ); document.write( "\n" ); document.write( "(1/2)^3x =8^2
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Algebra.Com's Answer #449133 by stanbon(75887)\"\" \"About 
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log x + log 4 =1
\n" ); document.write( "log(4x) = 1
\n" ); document.write( "4x = 10^1
\n" ); document.write( "4x = 10
\n" ); document.write( "x = 5/2
\n" ); document.write( "--------------------
\n" ); document.write( "log x - log 9 =3
\n" ); document.write( "log(x/9) = 3
\n" ); document.write( "x/9 = 10^3
\n" ); document.write( "x/9 = 1000
\n" ); document.write( "x = 9000
\n" ); document.write( "-------------------
\n" ); document.write( "(1/2)^3x =8^2
\n" ); document.write( "---
\n" ); document.write( "(2^-1)^(3x) = (2^3)^2
\n" ); document.write( "------
\n" ); document.write( "2^(-3x) = 2^(6)
\n" ); document.write( "---
\n" ); document.write( "-3x = 6
\n" ); document.write( "x = -2
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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