document.write( "Question 734781: log x + log 4 =1 please help with this\r
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document.write( "log x - log 9 =3\r
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document.write( "(1/2)^3x =8^2 \n" );
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Algebra.Com's Answer #449133 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! log x + log 4 =1 \n" ); document.write( "log(4x) = 1 \n" ); document.write( "4x = 10^1 \n" ); document.write( "4x = 10 \n" ); document.write( "x = 5/2 \n" ); document.write( "-------------------- \n" ); document.write( "log x - log 9 =3 \n" ); document.write( "log(x/9) = 3 \n" ); document.write( "x/9 = 10^3 \n" ); document.write( "x/9 = 1000 \n" ); document.write( "x = 9000 \n" ); document.write( "------------------- \n" ); document.write( "(1/2)^3x =8^2 \n" ); document.write( "--- \n" ); document.write( "(2^-1)^(3x) = (2^3)^2 \n" ); document.write( "------ \n" ); document.write( "2^(-3x) = 2^(6) \n" ); document.write( "--- \n" ); document.write( "-3x = 6 \n" ); document.write( "x = -2 \n" ); document.write( "=========== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=========== \n" ); document.write( " |