document.write( "Question 734765: Find three consecutive positive odd intergers such that the square of the smallest exceeds twice the largest by 7 | ONLY AN ALGEBRAIC SOLUTION WILL BE ACCEPTED?| \n" ); document.write( "

Algebra.Com's Answer #449120 by stanbon(75887) $\"\"$ $\"About$

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Find three consecutive positive odd intergers such that the square of the smallest exceeds twice the largest by 7
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\n" ); document.write( "1st: 2x-3
\n" ); document.write( "2nd: 2x-1
\n" ); document.write( "3rd: 2x+1
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\n" ); document.write( "Equation:
\n" ); document.write( "(2x-3)^2 = 2(2x+1)+7
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\n" ); document.write( "4x^2 -12x + 9 = 4x+9
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\n" ); document.write( "4x^2 -16x = 0
\n" ); document.write( "Factor:
\n" ); document.write( "4x(x-4) = 0
\n" ); document.write( "x = 0 or x = 4
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\n" ); document.write( "If x = 0::
\n" ); document.write( "1st: -3
\n" ); document.write( "2nd: -1
\n" ); document.write( "3rd: 1
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\n" ); document.write( "If x = 4
\n" ); document.write( "1st: 5
\n" ); document.write( "2nd: 7
\n" ); document.write( "3rd: 9
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\n" ); document.write( "Since you want positive odd only the x=4 set is acceptable.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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