document.write( "Question 734675: Please help me solve this question: \r
\n" ); document.write( "\n" ); document.write( "Show that the equation has at least one real root.\r
\n" ); document.write( "\n" ); document.write( "a) cosx=x^3\r
\n" ); document.write( "\n" ); document.write( "b)x^(5)-x^(2)+2x+3=0
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Algebra.Com's Answer #449082 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
a) Consider \"f%28x%29=cos%28x%29-x%5E3\"
\n" ); document.write( "It is a continuous function.
\n" ); document.write( "\"f%280%29=cos%280%29-0%5E3=1%3E0\"
\n" ); document.write( "\"f%28pi%2F2%29=cos%28pi%2F2%29-%28pi%2F2%29%5E3=0-pi%5E3%2F8=-pi%5E3%2F8%3C0\"
\n" ); document.write( "The continuous function \"f%28x%29\" is positive for \"x=0\" and negative for \"x=pi%2F2\" so it must have a zero somewhere in the (0,\"pi%2F2\") interval (according to the intermediate value theorem).
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\n" ); document.write( "You could do something similar with \"g%28x%29=x%5E5-x%5E2%2B2x%2B3%3E0\".
\n" ); document.write( "You can easily see that \"g%280%29=3%3E0\" and \"g%28-10%29=-100000%2B100%2B20%2B3%3C0\" and that is as much as is needed to prove is that there is one real root.
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