document.write( "Question 734653: A water trough is constructed by bending a
\n" ); document.write( "4- by 6-foot rectangular sheet of metal down the middle and
\n" ); document.write( "attaching triangular ends (see the figure). If the volume of
\n" ); document.write( "the trough is 9 cubic feet, find the width correct to two decimal
\n" ); document.write( "places.
\n" ); document.write( "

Algebra.Com's Answer #449076 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
bend in the middle . you will get an isosceles triangle .\r
\n" ); document.write( "\n" ); document.write( "The height of triangle will be \"%28sqrt%283%29%2F2%29+%2A2\"
\n" ); document.write( "=\"sqrt%283%29\"\r
\n" ); document.write( "\n" ); document.write( "Area of triangle = (1/2) * base * height\r
\n" ); document.write( "\n" ); document.write( "A= sqrt(3)/2 * base\r
\n" ); document.write( "\n" ); document.write( "Length = 6 feet\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Volume of tank = 6*sqrt(3)/2 * base\r
\n" ); document.write( "\n" ); document.write( "9=sqrt(3)/2 * base\r
\n" ); document.write( "\n" ); document.write( "Base = width of tank = 6sqrt(3)
\n" ); document.write( "
\n" );