document.write( "Question 734581: How many mL of 95% alcohol are needed to prepare 60 mL of 30% alcohol \n" ); document.write( "

Algebra.Com's Answer #449049 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+a+\"$ = ml of 95% alcohol needed
\n" ); document.write( " $\"+.95a+\"$ = ml of alcohol in 95% solution
\n" ); document.write( "Let $\"+b+\"$ = ml of water needed
\n" ); document.write( "(1) $\"+a+%2B+b+=+60+\"$
\n" ); document.write( "(2) $\"+.95a+%2F+60+=+.3+\"$
\n" ); document.write( "--------------------
\n" ); document.write( "(2) $\"+.95a+=+18+\"$
\n" ); document.write( "(2) $\"+a+=+18.947+\"$
\n" ); document.write( "18.947 ml of 95% alcohol is needed\r
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