document.write( "Question 734575: need help with quadratic equation
\n" );
document.write( "such as \r
\n" );
document.write( "\n" );
document.write( "x^2 + 12x -64 = 0\r
\n" );
document.write( "\n" );
document.write( "x2 - 2x - 13 = 0 \n" );
document.write( "
Algebra.Com's Answer #449038 by lynnlo(4176)![]() ![]() ![]() You can put this solution on YOUR website! PROBLEM:(1) \n" ); document.write( "X^2+12X-64=0 \n" ); document.write( "(1)FIND COEFFICIENTS A,B,C \n" ); document.write( "A=1,B=12,C=-64 \n" ); document.write( "(2)PLUG IN VALUES \n" ); document.write( "X1,2====-B±√B^2-4AC/2A \n" ); document.write( "X1,2====-12±√12^2-4.1.(-64/2.1 \n" ); document.write( "(3)SIMPLIFY \n" ); document.write( "X1,2====-12±√400/2 \n" ); document.write( "(4)SOLVE FOR X \n" ); document.write( "X1,,=-12±√400/2=4 \n" ); document.write( "X2,,=-12√400/2=-16 \n" ); document.write( "X=4,-16 \n" ); document.write( "PROBLEM(2) \n" ); document.write( "X2-2X-13=0 \n" ); document.write( "X=1+√14,,X≈4.7417 \n" ); document.write( "X=1-√14,,X≈-2.7417 \n" ); document.write( " |