document.write( "Question 734532: \r
\n" ); document.write( "\n" ); document.write( "A lab needs to make 100 gallons of an 18% acid solution by mixing a 12% acid solution with a 20% solution. How many gallons of each solution are needed?
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Algebra.Com's Answer #449019 by checkley79(3341)\"\" \"About 
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100*.18=.20x+.12(100-x)
\n" ); document.write( "18=.20x+12-.12x
\n" ); document.write( ".20x-.12x=18-12
\n" ); document.write( ".08x=6
\n" ); document.write( "x=6/.08
\n" ); document.write( "x=75 gallons of 20% acid is used.
\n" ); document.write( "100-75=25 gallons of 12% acid is used.
\n" ); document.write( "proof:
\n" ); document.write( "100*18=.20*75+.12*25
\n" ); document.write( "18=15+3
\n" ); document.write( "18=18
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