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document.write( "A lab needs to make 100 gallons of an 18% acid solution by mixing a 12% acid solution with a 20% solution. How many gallons of each solution are needed? \n" );
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Algebra.Com's Answer #449019 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! 100*.18=.20x+.12(100-x) \n" ); document.write( "18=.20x+12-.12x \n" ); document.write( ".20x-.12x=18-12 \n" ); document.write( ".08x=6 \n" ); document.write( "x=6/.08 \n" ); document.write( "x=75 gallons of 20% acid is used. \n" ); document.write( "100-75=25 gallons of 12% acid is used. \n" ); document.write( "proof: \n" ); document.write( "100*18=.20*75+.12*25 \n" ); document.write( "18=15+3 \n" ); document.write( "18=18 \n" ); document.write( " \n" ); document.write( " |