document.write( "Question 734433: A pool has two pipes, A and B. The pool can be filled in 10 hours less by using pipe A than using pipe B. One day, pipe A was turned on for 10 hours before pipe B was also turned on. The pool was filled after 6 more hours. How long does it take pipe A alone to fill the pool?\r
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document.write( "PLEASE HELP! \n" );
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Algebra.Com's Answer #448984 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A pool has two pipes, A and B. \n" ); document.write( " The pool can be filled in 10 hours less by using pipe A than using pipe B. \n" ); document.write( " One day, pipe A was turned on for 10 hours before pipe B was also turned on. \n" ); document.write( " The pool was filled after 6 more hours. \n" ); document.write( " How long does it take pipe A alone to fill the pool? \n" ); document.write( ": \n" ); document.write( "let x = time required by pipe A alone \n" ); document.write( "then \n" ); document.write( "(x+10) = time required by pipe B alone \n" ); document.write( ": \n" ); document.write( "Let the completed job = 1 (a full pool) \n" ); document.write( ": \n" ); document.write( "A shared work equation, (pipe A on for 16 hrs): \n" ); document.write( " \n" ); document.write( "multiply by x(x+10) to clear the denominators, resulting in: \n" ); document.write( "16(x+10) + 6x = x(x+10) \n" ); document.write( "16x + 160 + 6x = x^2 + 10x \n" ); document.write( "combine like terms to form a quadratic equation on the right: \n" ); document.write( "0 = x^2 + 10x - 22x - 160 \n" ); document.write( "x^2 - 12x - 160 = 0 \n" ); document.write( "factors to \n" ); document.write( "(x-20)(x+8) = 0 \n" ); document.write( "the positive solution \n" ); document.write( "x = 20 hrs for pipe A to fill the tank \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this \n" ); document.write( " \n" ); document.write( ".8 + .2 = 1\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |