document.write( "Question 734433: A pool has two pipes, A and B. The pool can be filled in 10 hours less by using pipe A than using pipe B. One day, pipe A was turned on for 10 hours before pipe B was also turned on. The pool was filled after 6 more hours. How long does it take pipe A alone to fill the pool?\r
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Algebra.Com's Answer #448984 by ankor@dixie-net.com(22740)\"\" \"About 
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A pool has two pipes, A and B.
\n" ); document.write( " The pool can be filled in 10 hours less by using pipe A than using pipe B.
\n" ); document.write( " One day, pipe A was turned on for 10 hours before pipe B was also turned on.
\n" ); document.write( " The pool was filled after 6 more hours.
\n" ); document.write( " How long does it take pipe A alone to fill the pool?
\n" ); document.write( ":
\n" ); document.write( "let x = time required by pipe A alone
\n" ); document.write( "then
\n" ); document.write( "(x+10) = time required by pipe B alone
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\n" ); document.write( "Let the completed job = 1 (a full pool)
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\n" ); document.write( "A shared work equation, (pipe A on for 16 hrs):
\n" ); document.write( "\"16%2Fx\" + \"6%2F%28%28x%2B10%29%29\" = 1
\n" ); document.write( "multiply by x(x+10) to clear the denominators, resulting in:
\n" ); document.write( "16(x+10) + 6x = x(x+10)
\n" ); document.write( "16x + 160 + 6x = x^2 + 10x
\n" ); document.write( "combine like terms to form a quadratic equation on the right:
\n" ); document.write( "0 = x^2 + 10x - 22x - 160
\n" ); document.write( "x^2 - 12x - 160 = 0
\n" ); document.write( "factors to
\n" ); document.write( "(x-20)(x+8) = 0
\n" ); document.write( "the positive solution
\n" ); document.write( "x = 20 hrs for pipe A to fill the tank
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\n" ); document.write( "Check this
\n" ); document.write( "\"16%2F20\" + \"6%2F30\" =
\n" ); document.write( ".8 + .2 = 1\r
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