document.write( "Question 734457: log10x-log(x-3)=log2 \n" ); document.write( "
Algebra.Com's Answer #448948 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\"log%2810x%29-log%28x-3%29=log%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810x%2F%28x-3%29%29=log%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"10x%2F%28x-3%29=2\"\r
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\n" ); document.write( "\n" ); document.write( "\"10x=2%28x-3%29\"\r
\n" ); document.write( "\n" ); document.write( "\"10x=2x-6\"\r
\n" ); document.write( "\n" ); document.write( "\"10x-2x=-6\"\r
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\n" ); document.write( "\n" ); document.write( "\"8x=-6\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=-6%2F8\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=-3%2F4\"\r
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