document.write( "Question 734327: x/6 + 6/7(6x + 7)=898 If anyone could possibly explain some of the steps or where to begin i'd greatly appreciate it thanks. \n" ); document.write( "
Algebra.Com's Answer #448912 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
\"x%2F6\" + \"6%2F7\"(6x + 7)=898
\n" ); document.write( "get rid of those annoying denominators
\n" ); document.write( "multiply equation by the least common multiple of 6 & 7, which is 42
\n" ); document.write( "42*\"x%2F6\" + 42*\"6%2F7\"(6x + 7)= 42(898)
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\n" ); document.write( "cancel the denominators
\n" ); document.write( "7x + 6*6(6x+7) = 37716
\n" ); document.write( "7x + 36(6x+7) = 37716
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\n" ); document.write( "multiply what's inside the brackets
\n" ); document.write( "7x + 216x + 252 = 37716
\n" ); document.write( "223x = 37716 - 252
\n" ); document.write( "223x = 37464
\n" ); document.write( "x = \"37464%2F223\"
\n" ); document.write( "x = 168
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\n" ); document.write( "Alot of math here, check the solution in the original problem
\n" ); document.write( "\"168%2F6\" + \"6%2F7\"(6(168) + 7)=898
\n" ); document.write( "28 + \"6%2F7\"(1008 + 7)=898
\n" ); document.write( "28 + \"6%2F7\"(1015)=898
\n" ); document.write( "28 + 870 = 898
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\n" ); document.write( "Did I make this understandable to you, this fine Spring morning!? C
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