document.write( "Question 734336: \r
\n" );
document.write( "
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "How many 4 person committees can be formed out of a class of 22 students?
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #448896 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! FIRST COMMITTEE: \n" ); document.write( "22*21*20*19=175,560 POSSIBILITIES. \n" ); document.write( "SECOND COMMITTEE: \n" ); document.write( "18*17*16*15=73,440 DITTO. \n" ); document.write( "THIRD COMMITTEE: \n" ); document.write( "14*13*12*11=24.024 DITTO. \n" ); document.write( "FOURTH COMMITTEE: \n" ); document.write( "10*9*8*7=5,040 DITTO. \n" ); document.write( "FIFTH COMMITTEE: \n" ); document.write( "6*5*4*3=360 DITTO. \n" ); document.write( "THE LAST 2 PEOPLE ARE NOT SELECTED FOR ANY COMMITTEE. \n" ); document.write( " |