document.write( "Question 734344: Please help/Fill in the blanks!!!!\r
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\n" ); document.write( "\n" ); document.write( "Given x=-y^2+4y+1, \r
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Algebra.Com's Answer #448887 by josgarithmetic(39618) $\"\"$ $\"About$

You can put this solution on YOUR website!
Complete the square for y. Put resulting equation into standard form. \r
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\n" ); document.write( "\n" ); document.write( "Omitting the completing of the square in this solution posting, the standard form equation should be $\"%28-1%29%28y-2%29%5E2=x-5\"$ . If you are at least somewhat familiar with quadratic equations and parabolas, you will understand that $\"y%5E2=x\"$ has vertex at the origin and the graph opens toward the right. This then would means that $\"-y%5E2=x\"$ opens to the left. Compare this with YOUR equation in standard form: Your equation opens to the left. [ $\"-y%5E2=x\"$ would be same as $\"%28-1%29y%5E2=x\"$ ].\r
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\n" ); document.write( "\n" ); document.write( "Compared to standard position, 5 units to the right and 2 units up. That information comes by reading it from the standard form for your equation, directly. See, $\"%28-1%29%28y-2%29%5E2=x-5\"$ , vertex point (h, k) is (5, 2). This is based on the symbolic model, $\"a%28y-k%29%5E2=x-h\"$ , standard form for a parabola with axis parallel to the x axis. \n" ); document.write( "

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