document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=734296>Question 734296</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I convert y=27(1/3)^(2x)into logarithmic form?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #448834 by </B><A HREF=/tutors/aboutme.mpl?userid=lynnlo><B>lynnlo(4176)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lynnlo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=448834\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Y=27(1/3)^(2X) IN LOGARITHMIC FORM:<BR>\n" );
document.write( "lny=ln27+2x*ln(1/3)<BR>\n" );
document.write( "lny=ln27-2x*ln3<BR>\n" );
document.write( "ln27-lny=2xln3<BR>\n" );
document.write( "ln(27)/y)=2*ln3<BR>\n" );
document.write( "2x=ln(27/y)/ln(3)=log3(27/y)<BR>\n" );
document.write( "X=1/2log3(27/y) </SPAN>\n" );
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