document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=64216>Question 64216</A>: <I><SPAN STYLE=\"word-break: break-all;\"> FIND AN EXPONENTIAL FUNCTION OF THE FORM f(x)=ba^x+c WITH y-INTERCEPT 2, HORIZONTAL ASYMPTOTE y=-2, THAT PASSES THROUGH THE POINT P(1,4). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #44883 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=44883\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> FIND AN EXPONENTIAL FUNCTION OF THE FORM f(x)=ba^x+c WITH y-INTERCEPT 2, HORIZONTAL ASYMPTOTE y=-2, THAT PASSES THROUGH THE POINT P(1,4).<BR>\n" );
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document.write( "f(x)=ba^x+c<BR>\n" );
document.write( "f(x)=ba^x+c<BR>\n" );
document.write( "If the horizontal asmptote is y=-2, c=-2<BR>\n" );
document.write( "So, f(x)=ba^x-2<BR>\n" );
document.write( "If the y-intercept is 2, f passes through (0,2)<BR>\n" );
document.write( "So, 2=ba^0-2<BR>\n" );
document.write( "4=b(1)<BR>\n" );
document.write( "b=4<BR>\n" );
document.write( "So, f(x)=4a^x-2<BR>\n" );
document.write( "If the curve passes through (1,4),<BR>\n" );
document.write( "4=4a^1-2<BR>\n" );
document.write( "6=4a<BR>\n" );
document.write( "a=3/2<BR>\n" );
document.write( "FINALLY:<BR>\n" );
document.write( "y=4(3/2)^x-2 is the equation you want.<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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