document.write( "Question 734169: at 2:10 Joyce was 42 miles from home. At 2:30 she was 21 miles from home. find her average rate of travel. then find the slope. I do no that rate mean to divide problem but I am a little because I graph it can some one please help me to understand a little better \r
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document.write( " thanks Desiree
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Algebra.Com's Answer #448774 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! at 2:10 Joyce was 42 miles from home. At 2:30 she was 21 miles from home. \n" ); document.write( " find her average rate of travel. then find the slope. \n" ); document.write( ": \n" ); document.write( "The travel time from 2:10 to 2:30 is 20 min which is: 20/60 = \n" ); document.write( "During this time he traveled 21 mi \n" ); document.write( ": \n" ); document.write( "Speed = dist/time \n" ); document.write( ": \n" ); document.write( "s = \n" ); document.write( "s = 21 * 3 \n" ); document.write( "s = 63 mph \n" ); document.write( ": \n" ); document.write( "The equation, where d = distance from home \n" ); document.write( "d = -63t + 42 \n" ); document.write( ": \n" ); document.write( "The slope is -63 \n" ); document.write( ": \n" ); document.write( "the graph, vert is distance from home, horizontal is time in hrs \n" ); document.write( " |