document.write( "Question 734125: A new still unsharpened, wooden pencil has the form of a cylinder. It is 19cm long and has a diameter of 0.8cm.The cylinder hole for the core in the middle of the pencil has a diameter of 0.2cm\r
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Algebra.Com's Answer #448729 by mananth(16946)\"\" \"About 
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outer volume - inner volume = volume of wood for the pencil\r
\n" ); document.write( "\n" ); document.write( "outer radius =0.8/2 = 0.4 cm
\n" ); document.write( "length = 9 cm\r
\n" ); document.write( "\n" ); document.write( "inner radius = 0.2/2 = 0.1
\n" ); document.write( "length = 9 cmm\r
\n" ); document.write( "\n" ); document.write( "V cylinder = pir^2h\r
\n" ); document.write( "\n" ); document.write( "V(whole pencil) = pi * 0.4^2*9\r
\n" ); document.write( "\n" ); document.write( "V (core) = pi*0.1^2*9\r
\n" ); document.write( "\n" ); document.write( "V ( wood) = pi*0.4*2*9-pi*0.1^2*9\r
\n" ); document.write( "\n" ); document.write( "= 9*pi(0.4^2-0.1^2)
\n" ); document.write( "=4.24 cm^3\r
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