document.write( "Question 734003: Christin can jog to work in 3/4 of an hour. WHen she rides her bike, it takes her 1/3 of an hour. If she rides 12 miles per hour faster than she jogs, how far away is her work? Do not do any rounding. \n" ); document.write( "
Algebra.Com's Answer #448694 by josgarithmetic(39618)\"\" \"About 
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Using x = distance to travel to arrive at work,\r
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\n" ); document.write( "\n" ); document.write( "Fill some data into a table:\r
\n" ); document.write( "\n" ); document.write( "__________rate__________time___________distance
\n" ); document.write( "jog______(___)__________3/4____________x
\n" ); document.write( "ride_____(___)__________1/3____________x\r
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\n" ); document.write( "\n" ); document.write( "That information is enough to find the expressions for the two different rates:\r
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\n" ); document.write( "\n" ); document.write( "__________rate__________time___________distance
\n" ); document.write( "jog______(x(4/3))__________3/4____________x
\n" ); document.write( "ride_____(x(3/1))__________1/3____________x\r
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\n" ); document.write( "\n" ); document.write( "A relationship between the two rates is given. Riding is 12 mph faster than jogging, so \"3x=12%2Bx%284%2F3%29\", or \"3x=12%2B%284%2F3%29x\". Solve for x, the distance to work.
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