document.write( "Question 734009: Hi there!\r
\n" ); document.write( "\n" ); document.write( "Well I was wondering if I could please get some help finding the center and foci of this hyperbola. It would be good if I could see the work so I could understand the problem better. (y + 2) ^ 2 /4 - x ^ 2 / 12 = 1\r
\n" ); document.write( "\n" ); document.write( "thank you so much! \n" ); document.write( "
Algebra.Com's Answer #448689 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\"%28y+-+k%29+%5E+2+%2Fb%5E2++-+%28x-h%29+%5E+2+%2F+a%5E2+=+1\" where \"h\" and \"k\" are the coordinates of the center\r
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\n" ); document.write( "\n" ); document.write( "\"%28y+%2B+2%29%5E2+%2F4+-x%5E2+%2F12+=+1\"\r
\n" ); document.write( "\n" ); document.write( "\"k=-2\", \"h=0\",; so, the center is at (\"0\",\"-2\") \r
\n" ); document.write( "\n" ); document.write( "\"a%5E2=12\"...=> \"a=3.46\" ....the semi-transverse axis is \"3.46\" unit
\n" ); document.write( "long\r
\n" ); document.write( "\n" ); document.write( "\"b%5E2=4\"...=> \"b=2\"...the semi-conjugate axis is \"2\" units
\n" ); document.write( "long\r
\n" ); document.write( "\n" ); document.write( "focus: \"c%5E2=a%5E2%2Bb%5E2\"\r
\n" ); document.write( "\n" ); document.write( " \"c%5E2=12%2B4\"\r
\n" ); document.write( "\n" ); document.write( "\"c%5E2=16\"\r
\n" ); document.write( "\n" ); document.write( "\"c=sqrt%2816%29\"\r
\n" ); document.write( "\n" ); document.write( "\"c=4\" and \"c=-4\".....The foci are \"c\" units right and left of the center:\r
\n" ); document.write( "\n" ); document.write( "(\"0\",\"-2%2B4\")=(\"highlight%280%29\",\"highlight%282%29\")
\n" ); document.write( "and (\"0\",\"-2-4\")=(\"highlight%280%29\",\"highlight%28-6%29\")\r
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