document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=733990>Question 733990</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use Gauss's approach to find the following sums (do not use a formula).\r<BR>\n" );
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document.write( "a)1+2+3+4+...101\r<BR>\n" );
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document.write( "b)1+3+5+7+...103\r<BR>\n" );
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document.write( "Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #448659 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=448659\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use Gauss's approach to find the following sums (do not use a formula). <BR>\n" );
document.write( "a)1+2+3+4+...101<BR>\n" );
document.write( "n = 101<BR>\n" );
document.write( "S(n) = (n/2)(1st + last) = 101(102)/2 = 101*51 = 5151<BR>\n" );
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document.write( "b)1+3+5+7+...103<BR>\n" );
document.write( "n = 104/2 = 52<BR>\n" );
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document.write( "S(n) = (n/2)(1st + last) = 26(104) = 2704<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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