document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=733901>Question 733901</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I figure the expression for this sequence: 8, 10, 12, 14... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #448632 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=448632\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Common Difference: d = 2 (since 10-8 = 2, 12-10 = 2, etc etc)\r<BR>\n" );
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document.write( "First term: a1 = 8\r<BR>\n" );
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document.write( "nth term\r<BR>\n" );
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document.write( "an = a1 + d(n-1)\r<BR>\n" );
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document.write( "an = 8 + 2(n-1)\r<BR>\n" );
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document.write( "an = 8 + 2n-2\r<BR>\n" );
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document.write( "an = 2n + 6\r<BR>\n" );
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document.write( "So if n starts at n = 1, then the nth term is 2n + 6 </SPAN>\n" );
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