document.write( "Question 733804: Please help me find the axis of symmetry, the focus, directrix and vertex of the parabola.\r
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document.write( "(x+2) ^ 2 - 16 (y-1) = 0\r
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document.write( "thank you! \n" );
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Algebra.Com's Answer #448612 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! find the axis of symmetry, the focus, directrix and vertex of the parabola. \n" ); document.write( "(x+2) ^ 2 - 16 (y-1) = 0 \n" ); document.write( "-------------------------- \n" ); document.write( "Form of parabola opening up: \n" ); document.write( "(x+2)^2 = 16(y-1) \n" ); document.write( "------ \n" ); document.write( "Vertex: (-2,1) \n" ); document.write( "Axis of symmetry: x = -2 \n" ); document.write( "--- \n" ); document.write( "Since 4p = 16, p = 4 \n" ); document.write( "--- \n" ); document.write( "Directrix: y = -3 \n" ); document.write( "Focus:: (-2,5) \n" ); document.write( "========================== \n" ); document.write( "16y-16 = (x+2)^2 \n" ); document.write( "16y = (x+2)^2+16 \n" ); document.write( "y = (1/16)(x+2)^2+1 \n" ); document.write( " \n" ); document.write( "=================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=========================== \n" ); document.write( " |