document.write( "Question 733780: is there a solution for this problem? problem : x^2-2x-24=0......I dont understand it
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #448596 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( "x²-2x-24 = 0\r\n" );
document.write( "\r\n" );
document.write( "We must factor that. Here's how:\r\n" );
document.write( "\r\n" );
document.write( "Think of all the ways to write 24 as the product of 2 integers\r\n" );
document.write( "starting with 24·1:\r\n" );
document.write( "\r\n" );
document.write( "24·1\r\n" );
document.write( "12·2\r\n" );
document.write( " 8·3\r\n" );
document.write( " 6·4\r\n" );
document.write( "\r\n" );
document.write( "Since the sign of 24 is -, subtract these out to the side:\r\n" );
document.write( "\r\n" );
document.write( "24·1   24-1 = 23\r\n" );
document.write( "12·2   12-2 = 10 \r\n" );
document.write( " 8·3    8-3 = 5\r\n" );
document.write( " 6·4    6-4 = 2\r\n" );
document.write( "\r\n" );
document.write( "Look at the given equation:  x²-2x-24 = 0\r\n" );
document.write( "\r\n" );
document.write( "The middle term's coefficient (in absolute value) is 2, and\r\n" );
document.write( "it is listed above in the differences, with 6 and 4.\r\n" );
document.write( "So we write:\r\n" );
document.write( "\r\n" );
document.write( "(x 6)(x 4) = 0\r\n" );
document.write( "\r\n" );
document.write( "and since the middle term is negative, put a - sign with\r\n" );
document.write( "the larger, 6, and a + sign with the smaller 4\r\n" );
document.write( "\r\n" );
document.write( "(x-6)(x+4) = 0\r\n" );
document.write( "\r\n" );
document.write( "Now since the product of (x-6) and (x+4) equals 0, that means\r\n" );
document.write( "that one of those equals 0.  So we set each  DISABLED_event_one=  0:\r\n" );
document.write( "\r\n" );
document.write( "x-6 = 0;   x+4 = 0\r\n" );
document.write( "  x = 6;     x = -4\r\n" );
document.write( "\r\n" );
document.write( "So there are two solutions, 6 and -4.\r\n" );
document.write( "\r\n" );
document.write( "We check x = 6 by substituting (6) for x in the original\r\n" );
document.write( "equation:\r\n" );
document.write( "\r\n" );
document.write( "    x²-2x-24 = 0\r\n" );
document.write( "(6)²-2(6)-24 = 0\r\n" );
document.write( "    36-12-24 = 0\r\n" );
document.write( "           0 = 0\r\n" );
document.write( "So x = 6 is a solution:\r\n" );
document.write( "\r\n" );
document.write( "We check x = -4 by substituting (-4) for x in the original\r\n" );
document.write( "equation:\r\n" );
document.write( "\r\n" );
document.write( "      x²-2x-24 = 0\r\n" );
document.write( "(-4)²-2(-4)-24 = 0\r\n" );
document.write( "       16+8-24 = 0\r\n" );
document.write( "             0 = 0\r\n" );
document.write( "So x = -4 is also a solution:\r\n" );
document.write( "\r\n" );
document.write( "So we are now certain that x=6 and x=-4 are the solutions\r\n" );
document.write( "to the given equation.\r\n" );
document.write( "\r\n" );
document.write( "Edwin
\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );