document.write( "Question 733780: is there a solution for this problem? problem : x^2-2x-24=0......I dont understand it
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Algebra.Com's Answer #448596 by Edwin McCravy(20055)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "x²-2x-24 = 0\r\n" ); document.write( "\r\n" ); document.write( "We must factor that. Here's how:\r\n" ); document.write( "\r\n" ); document.write( "Think of all the ways to write 24 as the product of 2 integers\r\n" ); document.write( "starting with 24·1:\r\n" ); document.write( "\r\n" ); document.write( "24·1\r\n" ); document.write( "12·2\r\n" ); document.write( " 8·3\r\n" ); document.write( " 6·4\r\n" ); document.write( "\r\n" ); document.write( "Since the sign of 24 is -, subtract these out to the side:\r\n" ); document.write( "\r\n" ); document.write( "24·1 24-1 = 23\r\n" ); document.write( "12·2 12-2 = 10 \r\n" ); document.write( " 8·3 8-3 = 5\r\n" ); document.write( " 6·4 6-4 = 2\r\n" ); document.write( "\r\n" ); document.write( "Look at the given equation: x²-2x-24 = 0\r\n" ); document.write( "\r\n" ); document.write( "The middle term's coefficient (in absolute value) is 2, and\r\n" ); document.write( "it is listed above in the differences, with 6 and 4.\r\n" ); document.write( "So we write:\r\n" ); document.write( "\r\n" ); document.write( "(x 6)(x 4) = 0\r\n" ); document.write( "\r\n" ); document.write( "and since the middle term is negative, put a - sign with\r\n" ); document.write( "the larger, 6, and a + sign with the smaller 4\r\n" ); document.write( "\r\n" ); document.write( "(x-6)(x+4) = 0\r\n" ); document.write( "\r\n" ); document.write( "Now since the product of (x-6) and (x+4) equals 0, that means\r\n" ); document.write( "that one of those equals 0. So we set each DISABLED_event_one= 0:\r\n" ); document.write( "\r\n" ); document.write( "x-6 = 0; x+4 = 0\r\n" ); document.write( " x = 6; x = -4\r\n" ); document.write( "\r\n" ); document.write( "So there are two solutions, 6 and -4.\r\n" ); document.write( "\r\n" ); document.write( "We check x = 6 by substituting (6) for x in the original\r\n" ); document.write( "equation:\r\n" ); document.write( "\r\n" ); document.write( " x²-2x-24 = 0\r\n" ); document.write( "(6)²-2(6)-24 = 0\r\n" ); document.write( " 36-12-24 = 0\r\n" ); document.write( " 0 = 0\r\n" ); document.write( "So x = 6 is a solution:\r\n" ); document.write( "\r\n" ); document.write( "We check x = -4 by substituting (-4) for x in the original\r\n" ); document.write( "equation:\r\n" ); document.write( "\r\n" ); document.write( " x²-2x-24 = 0\r\n" ); document.write( "(-4)²-2(-4)-24 = 0\r\n" ); document.write( " 16+8-24 = 0\r\n" ); document.write( " 0 = 0\r\n" ); document.write( "So x = -4 is also a solution:\r\n" ); document.write( "\r\n" ); document.write( "So we are now certain that x=6 and x=-4 are the solutions\r\n" ); document.write( "to the given equation.\r\n" ); document.write( "\r\n" ); document.write( "Edwin\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |