document.write( "Question 733694: Find the surface area
\n" ); document.write( "a. cylinder and cone 6mm, h=10mm, r=4mm\r
\n" ); document.write( "\n" ); document.write( "b. cone r=10mm, h=25mm\r
\n" ); document.write( "\n" ); document.write( "c. square base 50mm, 40mm, 40mm
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Algebra.Com's Answer #448569 by rothauserc(4718)\"\" \"About 
You can put this solution on YOUR website!
Note that we do not need the 6mm measurement for surface area calculations!\r
\n" ); document.write( "\n" ); document.write( "Surface Area (SA) of cylinder (two ends are circles) formula is\r
\n" ); document.write( "\n" ); document.write( "SA = 2*pi*radius squared + 2*pi*radius*height
\n" ); document.write( "SA = 2*22/7*4 squared + 2*22/7*4*10, therefore SA = 100.6 + 251.4 = 352 square mm's\r
\n" ); document.write( "\n" ); document.write( "Surface area of cone (one end is a circle) formula is\r
\n" ); document.write( "\n" ); document.write( "SA = pi*radius squared + pi * radius * hypotenuse (s)
\n" ); document.write( "first calculate s squared = radius squared + height squared,
\n" ); document.write( " s squared = 10 squared + 25 squared = 100+625=725
\n" ); document.write( " s = square root of 725 = 26.9 mm
\n" ); document.write( "SA = 22/7*10 squared + 22/7*10*26.9 = 2200/7 + 22/7*10*26.9=314.3+825.4=1159.7 square mm's\r
\n" ); document.write( "\n" ); document.write( "Surface area of rectangular solid is\r
\n" ); document.write( "\n" ); document.write( "the square base is 40mm by 40mm = 1600 square mm and there are two ends so total for 2 square ends is 3200 square mm\r
\n" ); document.write( "\n" ); document.write( "now there are 4 sides that are 50 by 40 or 2000 square mm * 4 = 8000 square mm\r
\n" ); document.write( "\n" ); document.write( "adding the two calculations\r
\n" ); document.write( "\n" ); document.write( "SA = 3200 + 8000 = 11200 square mm's\r
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