document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=733704>Question 733704</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i need to know how to get y^2-12y-x^2-2x= -31 in standard form<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #448554 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=448554\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y^2-12y-x^2-2x= -31 in standard form<BR>\n" );
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document.write( "Complete the square on the x-terms and on the y-terms.<BR>\n" );
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document.write( "y^2 - 12y + (12/2)^2 - (x^2 + 2x + (2/2)^2) = -31 + (12/2)^2 - (2/2)^2<BR>\n" );
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document.write( "Factor:<BR>\n" );
document.write( "(y-6)^2 - (x+1)^2 = 4<BR>\n" );
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document.write( "[(y-6)^2 / 4] - [(x+1)^2/ 4] = 1<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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