document.write( "Question 733600: A cyclist and a jogger start in a town and want to end 12 miles away. The cyclists rate is 2xs the jogger. He arrives 1.2 hours before the jogger. What is the rate of the cyclist. \n" ); document.write( "
Algebra.Com's Answer #448542 by ankor@dixie-net.com(22740)\"\" \"About 
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A cyclist and a jogger start in a town and want to end 12 miles away.
\n" ); document.write( " The cyclists rate is 2xs the jogger. He arrives 1.2 hours before the jogger. What is the rate of the cyclist.\r
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\n" ); document.write( "let r = rate of the jogger
\n" ); document.write( "then
\n" ); document.write( "2r = rate of the cyclist
\n" ); document.write( ":
\n" ); document.write( "Write a time equation: time = dist/rate
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\n" ); document.write( "jogger time - cyclist time = 1.2 hr
\n" ); document.write( "\"12%2Fr\" - \"12%2F%282r%29\" = 1.2
\n" ); document.write( "reduce the fraction
\n" ); document.write( "\"12%2Fr\" - \"6%2Fr\" = 1.2
\n" ); document.write( "multiply by r
\n" ); document.write( "12 - 6 = 1.2r
\n" ); document.write( "6 = 1.2r
\n" ); document.write( "r = 6/1.2
\n" ); document.write( "r = 5 mph rate of the jogger
\n" ); document.write( "then
\n" ); document.write( "2(5) = 10 mph rate of the cyclist
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\n" ); document.write( "check this; find the actual time of each
\n" ); document.write( "12/5 = 2.4 hrs
\n" ); document.write( "12/10= 1.2 hrs
\n" ); document.write( "---------------
\n" ); document.write( "differ: 1.2 hrs
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