document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=733622>Question 733622</A>: <I><SPAN STYLE=\"word-break: break-all;\"> half the perimeter of a rectangular lot, which is 50 feet longer than it is wide, is 350 feet. what are the dimensions of the lot? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #448508 by </B><A HREF=/tutors/aboutme.mpl?userid=chana><B>chana(69)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=chana><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=448508\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter of the rectangle = 2L+2B<BR>\n" );
document.write( "L=B+50<BR>\n" );
document.write( "half the perimeter of a rectangular lot, which is 50 feet longer than it is wide, is 350 feet<BR>\n" );
document.write( "So,<BR>\n" );
document.write( ".5*(2* (B+50))+(2B))= 350<BR>\n" );
document.write( "4B+100=700<BR>\n" );
document.write( "solving for B we get, B as 150 feet<BR>\n" );
document.write( "And L= 150+50<BR>\n" );
document.write( "      =200 feet </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );