document.write( "Question 733592: My car's radiator is full of an antifreeze-water mixture that is 75% water and 25% antifreeze. I left the cap off while driving and a lot of the mixture leaked out. I filled up the radiator with 9 quarts of water as I was out of antifreeze and then foud the mixture was only 12% antifreeze. What is the capacity of the radiator.\r
\n" ); document.write( "\n" ); document.write( "I tried setting my problem up as .75(.25)=18.75 and .12(.88)=10.56 This answer got me nowhere and now I am stuck. Please help!
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Algebra.Com's Answer #448492 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+x+\" = the radiator's capacity in quarts
\n" ); document.write( "After losing mixture, \"+9+\" quarts of water filled the radiator,
\n" ); document.write( "so \"+9+\" quarts of mixture was lost
\n" ); document.write( "-------------
\n" ); document.write( "You started with \"+.25x+\" quarts of antifreeze and lost
\n" ); document.write( "\"+.25%2A9+=+2.25+\" quarts, so there is \"+.25x+-+2.25+\" quarts
\n" ); document.write( "of antifreeze in the radiator before the water is added
\n" ); document.write( "-------------
\n" ); document.write( "\"+%28+.25x+-+2.25+%29+%2F+x+=+.12+\"
\n" ); document.write( "\"+.25x+-+2.25+=+.12x+\"
\n" ); document.write( "\"+.13x+=+2.25+\"
\n" ); document.write( "\"+x+=+17.3077+\"
\n" ); document.write( "The capacity of the radiator is 17.3077 quarts
\n" ); document.write( "check answer:
\n" ); document.write( "There is \"+.25%2A17.3077+=+4.327+\" quarts of antifreeze to start
\n" ); document.write( "\"+.25%2A9+=+2.25+\" quarts of antifreeze were lost
\n" ); document.write( "\"+4.327+-+2.25+=+2.077+\" quarts of antifreeze left
\n" ); document.write( "After water is added,
\n" ); document.write( "\"+2.077+%2F+17.3077+=+.120004+\"
\n" ); document.write( "close enough
\n" ); document.write( "Hope I got it\r
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