document.write( "Question 733581: i dont understand what they are asking. here's the question : using the discriminant tell whether the equation has two solutions,one solution,or no real solution. problem: x^2-5x+6=0......how do i solve this equation? \n" ); document.write( "

Algebra.Com's Answer #448479 by sachi(548) $\"\"$ $\"About$

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in an eqn ax^2+bx+c=0 the discriminant=b^2-4ac
\n" ); document.write( "& the solns are [-b+-sqrt(b^2-4ac)]/2a
\n" ); document.write( "now if 1)b^2=4ac then there is one solution i.e -b/2a
\n" ); document.write( " if 2)b^2>4ac then there are two solutions i.e [-b+-sqrt(b^2-4ac)]/2a
\n" ); document.write( "but if 3)b^2<4ac then there are no real solutions asthe sqrt will have no real value
\n" ); document.write( "now here in x^2-5x+6=0 a=1,b=-5& c=6
\n" ); document.write( "so b^2-4ac =1
\n" ); document.write( "so there are two solutions by 2) above 3 & 2 ans \n" ); document.write( "

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