document.write( "Question 733501: A girl lives 6 miles from school. On her way home, she skates 4 miles before a wheel falls off her skates. It then takes her the same amount of time to walk the rest of the way home as it took her to skate the first 4 miles. She can skate 3mph faster than she walks. How fast can she skate? \n" ); document.write( "
Algebra.Com's Answer #448449 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! to solve this problem recognize that this is a rate problem with the following equation\r \n" ); document.write( "\n" ); document.write( "rate times time = distance\r \n" ); document.write( "\n" ); document.write( "let t be the time it takes her to skate 4 miles and also the time it takes her to walk 2 miles, also let r+3 be her skating rate and r be her walking rate\r \n" ); document.write( "\n" ); document.write( "so here we have \r \n" ); document.write( "\n" ); document.write( "(r+3)t + rt = 6 and\r \n" ); document.write( "\n" ); document.write( "(r+3)t = 4 and rt = 2\r \n" ); document.write( "\n" ); document.write( "expand the first equation and we get\r \n" ); document.write( "\n" ); document.write( "rt + 3t + rt = 6\r \n" ); document.write( "\n" ); document.write( "substitute 2 for rt and we have\r \n" ); document.write( "\n" ); document.write( "2 + 3t + 2 = 6 and 3t = 2 with t = 2/3\r \n" ); document.write( "\n" ); document.write( "her walking rate is r times 2/3 = 2 or r = 3 mph and her skating rate is 3 + 3 or 6 mph \n" ); document.write( " \n" ); document.write( " |