document.write( "Question 733409: \r
\n" ); document.write( "\n" ); document.write( "the product of two positive numbers is 65. find the two numbers if one number is 3 more than twice the other?
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Algebra.Com's Answer #448386 by checkley79(3341)\"\" \"About 
You can put this solution on YOUR website!
XY=65 OR X=65/Y
\n" ); document.write( "X=2Y+3
\n" ); document.write( "65/Y=2Y+3 CROSS MULTIPLY.
\n" ); document.write( "Y(2Y+3)=65
\n" ); document.write( "2Y*2+3Y=65
\n" ); document.write( "2Y^2+3Y-65=0
\n" ); document.write( "(2Y+13)(Y-5)=0
\n" ); document.write( "Y-5=0
\n" ); document.write( "Y=5 ANS.
\n" ); document.write( "X=65/5
\n" ); document.write( "X=13 ANS.
\n" ); document.write( "PROOF:
\n" ); document.write( "13=2*5+3
\n" ); document.write( "13=10+3
\n" ); document.write( "13=13
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