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document.write( "the product of two positive numbers is 65. find the two numbers if one number is 3 more than twice the other? \n" );
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Algebra.Com's Answer #448386 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! XY=65 OR X=65/Y \n" ); document.write( "X=2Y+3 \n" ); document.write( "65/Y=2Y+3 CROSS MULTIPLY. \n" ); document.write( "Y(2Y+3)=65 \n" ); document.write( "2Y*2+3Y=65 \n" ); document.write( "2Y^2+3Y-65=0 \n" ); document.write( "(2Y+13)(Y-5)=0 \n" ); document.write( "Y-5=0 \n" ); document.write( "Y=5 ANS. \n" ); document.write( "X=65/5 \n" ); document.write( "X=13 ANS. \n" ); document.write( "PROOF: \n" ); document.write( "13=2*5+3 \n" ); document.write( "13=10+3 \n" ); document.write( "13=13 \n" ); document.write( " |