document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=731745>Question 731745</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of four times a number and 9 is same as one-third that number increased by 31. Find the number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #448360 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=448360\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This word problem can be represented by this equation\r<BR>\n" );
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document.write( "4n + 9 = 1/3n + 31\r<BR>\n" );
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document.write( "we subtract 9 from both sides of the equation\r<BR>\n" );
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document.write( "4n = 1/3n + 22\r<BR>\n" );
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document.write( "we then multiply both sids of the equation by 3\r<BR>\n" );
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document.write( "12n = n + 66\r<BR>\n" );
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document.write( "subtact n from both sides\r<BR>\n" );
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document.write( "11n = 66\r<BR>\n" );
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document.write( "and dividing both sides by 11 we get n = 6  </SPAN>\n" );
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