document.write( "Question 733314: find two consecutive positive integers such that the sum of their squares is 61 \n" ); document.write( "
Algebra.Com's Answer #448354 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! let i represent a positive integer and i+1 be the consecutive integer. We know that \n" ); document.write( " i squared + (i+1)squared = 61\r \n" ); document.write( "\n" ); document.write( "squaring both terms\r \n" ); document.write( "\n" ); document.write( " i squared + i squared + 2i + 1 = 61\r \n" ); document.write( "\n" ); document.write( "combining terms and subtracting 1 from both sides of equal sign we have\r \n" ); document.write( "\n" ); document.write( " 2 i squared + 2i = 60\r \n" ); document.write( "\n" ); document.write( "divide equation by 2\r \n" ); document.write( "\n" ); document.write( " i squared + i = 30\r \n" ); document.write( "\n" ); document.write( "we now have the quadratic equation\r \n" ); document.write( "\n" ); document.write( " i squared + i - 30 = 0\r \n" ); document.write( "\n" ); document.write( "factoring the quadratic equation, we have\r \n" ); document.write( "\n" ); document.write( " ( i + 6 ) * (i - 5) = 0\r \n" ); document.write( "\n" ); document.write( "this gives us two equations\r \n" ); document.write( "\n" ); document.write( " i + 6 = 0 and i - 5 = 0\r \n" ); document.write( "\n" ); document.write( "now the integers are required to be positive so the solution is\r \n" ); document.write( "\n" ); document.write( " i = 5 and i+1 = 6\r \n" ); document.write( "\n" ); document.write( "and we see that\r \n" ); document.write( "\n" ); document.write( " 5 squared + 6 squared = 61\r \n" ); document.write( "\n" ); document.write( "namely,\r \n" ); document.write( "\n" ); document.write( " 25 + 36 = 61\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |