document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=733250>Question 733250</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A metal cube of side l (this is the letter L lower case not no.1) is heated and each side increases by 1%. To the nearest percent find the increase in surface area & volume.<BR>\n" );
document.write( "Please show workings down page if you can. It makes more sense to me. Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #448316 by </B><A HREF=/tutors/aboutme.mpl?userid=sachi><B>sachi(548)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sachi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sachi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=448316\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A metal cube of side l  is heated and each side increases by 1%<BR>\n" );
document.write( "so the original side= l & after heating side=1.01l<BR>\n" );
document.write( "so the original surface area=6l^2 & after heating surface area=6x(1.01)^2xl^2<BR>\n" );
document.write( "increase in surface area=6x(1.01)^2xl^2-6l^2=6l^2x(1.0201-1)=0.0201*6l^2<BR>\n" );
document.write( "% increase in surface area=6l^2x(0.0201)*100/6l^2=2.01 %\r<BR>\n" );
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document.write( "now the original volume=l^3 & after heating volume=(1.01l)^3=1.030301l^3<BR>\n" );
document.write( "so the increase in volume=1.030301l^3-l^3=0.030301*l^3<BR>\n" );
document.write( "% increase in volume=0.030301*l^3*100/l^3=3.0301 %<BR>\n" );
document.write( "ans\r<BR>\n" );
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document.write( " </SPAN>\n" );
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