document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=733170>Question 733170</A>: <I><SPAN STYLE=\"word-break: break-all;\"> use log base 4 of 3 = .7925 and log base 4 of 5= 1.1610 to approximate the value of the expression log base 4 of 18. i was wondering how exactly to do this? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #448302 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=448302\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> use log base 4 of 3 = .7925 and log base 4 of 5= 1.1610 to approximate the value of the expression log base 4 of 18. i was wondering how exactly to do this?<BR>\n" );
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document.write( "18 = 3*3*2<BR>\n" );
document.write( "log(18) = 2*log(3) + log(2)<BR>\n" );
document.write( "2 = sqrt(4) --> log(2) = 1/2<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%284%2C18%29+=+2log%284%2C3%29+%2B+1%2F2 ALIGN=MIDDLE  ALT=\"log%284%2C18%29+=+2log%284%2C3%29+%2B+1%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "= 2.085 </SPAN>\n" );
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