document.write( "Question 733109: Hello,
\n" );
document.write( "If the probability of an event occuring is 10%, what is the probability that 2 or more times the event will occur in 30 , 40 or 50 trials. In the case of 30 trials I have been using the formula P(2 out of 30) = (30! / (2!*(30-2)!) *.01*(0.9*10^28). I get 22.7%. I think that I am calculating exactly 2 events occuring. How do I calculate at least 2 events?\r
\n" );
document.write( "\n" );
document.write( "Thanks.
\n" );
document.write( "Ross \n" );
document.write( "
Algebra.Com's Answer #448278 by stanbon(75887) ![]() You can put this solution on YOUR website! If the probability of an event occuring is 10%, what is the probability that 2 or more times the event will occur in 30 , 40 or 50 trials. In the case of 30 trials I have been using the formula P(2 out of 30) = (30! / (2!*(30-2)!) *.01*(0.9*10^28). I get 22.7%. I think that I am calculating exactly 2 events occuring. How do I calculate at least 2 events? \n" ); document.write( "------ \n" ); document.write( "Binomial Problem with n = 30 and p(event) = 0.1 \n" ); document.write( "---- \n" ); document.write( "P(2<= x <=30) = 1 - [P(x = 0)+P(x=1)] \n" ); document.write( "---- \n" ); document.write( "= 1 - [30C0(0.1)^0*0.9^30 + 30C1(0.1)^1*(0.9)^29] \n" ); document.write( "---- \n" ); document.write( "Now using a TI-84 calculator: \n" ); document.write( "= 1 - binomcdf(30,0.1,1) = 0.8163 \n" ); document.write( "============================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============================ \n" ); document.write( " \n" ); document.write( " |