document.write( "Question 732894:
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document.write( "Mike and Sarah buy books at a sale. Mike buys 3 hardcover books and 4 paperback books for $6.50. Sarah buys 2 hardcover books and 6 paperback books for $6.00. What is the cost, in dollars, of each hardcover book? \n" );
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Algebra.Com's Answer #448189 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! 3H+4P=6.50 MULTIPLY BY -1.5 & ADD. \n" ); document.write( "2H+6P=6.00 \n" ); document.write( "-4.5H-6P=-9.75 \n" ); document.write( "----------------------- \n" ); document.write( "-2.5H=-3.75 \n" ); document.write( "H=-3.75/-2.5 \n" ); document.write( "H=$1.50 COST OF EACH HARDCOVER BOOK. \n" ); document.write( "3*1.50+4P=6.50 \n" ); document.write( "4.50+4P=6.50 \n" ); document.write( "4P=6.50-4.50 \n" ); document.write( "4P=2.00 \n" ); document.write( "P=2.00/4 \n" ); document.write( "P=$.50 COST OF EACH PAPERBACK BOOK. \n" ); document.write( "PROOF: \n" ); document.write( "2*1.50+6*.50=6.00 \n" ); document.write( "3.00+3.00=6.00 \n" ); document.write( "6.00=6.00 \n" ); document.write( " |