document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=732935>Question 732935</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the relationship between temperatures in Celsius, C, and in Fahrenheit, F is given F=9/5C+32. If an area has a record low temperature of -30C what is the corresponding Fahrenheit? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #448153 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=448153\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the relationship between temperatures in Celsius, C, and in Fahrenheit, F is given F=9/5C+32. If an area has a record low temperature of -30C what is the corresponding Fahrenheit?<BR>\n" );
document.write( "--------------<BR>\n" );
document.write( "-30C = ((-30)*9 + 160)/5F<BR>\n" );
document.write( "= (-270 + 160)/5 F<BR>\n" );
document.write( "= -110/5 F<BR>\n" );
document.write( "= -22 F<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );