document.write( "Question 732957: An architect wants to draw a rectangle with a diagonal of 13 inches. The length of the rectangle is to be 2 inches more than twice the width. What dimensions should she make the rectangle? \r
\n" ); document.write( "\n" ); document.write( "This should be easy but I haven't been able to get to the correct answer. Please help.
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Algebra.Com's Answer #448148 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Let represent the width. Then must represent the length.\r
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\n" ); document.write( "\n" ); document.write( "The square of the width plus the square of the length equals the square of the diagonal -- Pythagoras said it, I believe it, that settles it.\r
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\n" ); document.write( "\n" ); document.write( "So:\r
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\n" ); document.write( "\n" ); document.write( "Solve the quadratic for , discarding the negative root. Or save yourself some work by remembering that 13, 12, 5 is a Pythagorean triple.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "Egw to Beta kai to Sigma
\n" ); document.write( "My calculator said it, I believe it, that settles it
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