document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=732711>Question 732711</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the digits of a two digit number is 11.  The original two-digit number is 5 more than 3 times the number with its digits reversed. Find the original number.   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #448101 by </B><A HREF=/tutors/aboutme.mpl?userid=vidhyak><B>vidhyak(98)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vidhyak><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=448101\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of the digits of a two digit number is 11. \r<BR>\n" );
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document.write( "The 2 digit numbers whose sum of digits add to 11 are 29, 38, 47, 56, 65, 74, 83, 92\r<BR>\n" );
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document.write( "The original two-digit number is 5 more than 3 times the number with its digits reversed\r<BR>\n" );
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document.write( "From the above statement, it is understood that the original  two-digit number is greater than the reversed number\r<BR>\n" );
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document.write( "so the number should be either 65, 74, 83 or 92\r<BR>\n" );
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document.write( "original number = 5 + 3(reversed number)\r<BR>\n" );
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document.write( "Let's apply the formula to 65, 74, 83, 92 to see which is correct\r<BR>\n" );
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document.write( "65 = 5 + 3(56) = 5 + 177 = 182 -------not correct<BR>\n" );
document.write( "74 = 5 + 3(47) = 5 + 141 = 146 -------not correct<BR>\n" );
document.write( "83 = 5 + 3(38) = 5 + 114 = 119 -------not correct\r<BR>\n" );
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document.write( "92 = 5 + 3(29) = 5 + 87 = 92 -------correct\r<BR>\n" );
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document.write( "92 is the number </SPAN>\n" );
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