document.write( "Question 732810: An investor invested a total of 2800 in two mutual funds. One fund earned a 6% profit while the other earned a 4% profit. If the investors total profit was $152, how much was invested in each mutual fund? \n" ); document.write( "

Algebra.Com's Answer #448075 by mananth(16946) $\"\"$ $\"About$

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Part I 6.00% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 4.00% per annum ------------ Amount invested = y
\n" ); document.write( " 2800
\n" ); document.write( "Interest----- 152.00
\n" ); document.write( "
\n" ); document.write( "Part I 6.00% per annum ---x
\n" ); document.write( "Part II 4.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 2800 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "6.00% x + 4.00% y= 152
\n" ); document.write( "Multiply by 100
\n" ); document.write( "6 x + 4 y= 15200.00 --------2
\n" ); document.write( "Multiply (1) by -6
\n" ); document.write( "we get
\n" ); document.write( "-6 x -6 y= -16800.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x -2 y= -1600
\n" ); document.write( "divide by -2
\n" ); document.write( " y = 800
\n" ); document.write( "Part I 6.00% $ 2000
\n" ); document.write( "Part II 4.00% $ 800
\n" ); document.write( "
\n" ); document.write( "CHECK
\n" ); document.write( "2000 --------- 6.00% ------- 120.00
\n" ); document.write( "800 ------------- 4.00% ------- 32.00
\n" ); document.write( "Total -------------------- 152.00
\n" ); document.write( " \n" ); document.write( "

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