document.write( "Question 732844: how to solve the sum of the digits of A 3-digit number is 16 if the digits are reversed and the resulting number added to the original number the sum is 1049 if the resulting number is subtracted from the original number the difference is 297 what is the number? \n" ); document.write( "
Algebra.Com's Answer #448072 by mananth(16946)![]() ![]() You can put this solution on YOUR website! First condition \n" ); document.write( "x+y+z=16................................(1) \n" ); document.write( "Second condition \n" ); document.write( "100x+10y+z+100z+10y+x=1049\r \n" ); document.write( "\n" ); document.write( "101x+20y+101z=1049............................(2)\r \n" ); document.write( "\n" ); document.write( "third condition \n" ); document.write( "100x+10y+z-(100z+10y+x)=297\r \n" ); document.write( "\n" ); document.write( "99x-99z=297 \n" ); document.write( "/99 \n" ); document.write( "x-z=3 \n" ); document.write( "x=z+3.......................................(3)\r \n" ); document.write( "\n" ); document.write( "substitute x in (1) & (2) \n" ); document.write( "z+3+y+z=16 \n" ); document.write( "y+2z=13...................(4) \n" ); document.write( "101(z+3)+20y+101z=1049 \n" ); document.write( "101z+303+20y+101z=1049 \n" ); document.write( "202z+20y=1049-303 \n" ); document.write( "202z+20y=746..................(5)\r \n" ); document.write( "\n" ); document.write( "1.00 y + 2.00 z = 13.00 \n" ); document.write( "Total value \n" ); document.write( "20.00 y + 202.00 z = 746.00 \n" ); document.write( "Eliminate y \n" ); document.write( "multiply (1)by 202.00 \n" ); document.write( "Multiply (2) by -2.00 \n" ); document.write( "202.00 y 404.00 z = 2626.00 \n" ); document.write( "-40.00 y -404.00 z = -1492.00 \n" ); document.write( "Add the two equations \n" ); document.write( "162.00 y = 1134.00 \n" ); document.write( "/ 162.00 \n" ); document.write( "y = 7 \n" ); document.write( "plug value of y in (1) \n" ); document.write( "1.00 y + 2.00 z = 13.00 \n" ); document.write( "7.00 + 2.00 z = 13.00 \n" ); document.write( " 2.00 z = 13.00 -7.00 \n" ); document.write( " 2.00 z = 6.00 \n" ); document.write( " z = 3 \n" ); document.write( "y=7,z=3,therefore x= 6\r \n" ); document.write( "\n" ); document.write( "100*6+70+3 \n" ); document.write( "673 is the number\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |