document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=732802>Question 732802</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An arithmetic series has first term 1000 and common difference -1.4.  calculate the value of the first negative term of the series, and the sum of all the positive terms </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #448070 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=448070\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a= 1000<BR>\n" );
document.write( "d= -1.4\r<BR>\n" );
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document.write( "1000/1.4 = 714.29\r<BR>\n" );
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document.write( "there are 714.29 =ve numbers<BR>\n" );
document.write( "add 1.4 you get 715.69<BR>\n" );
document.write( "so 716th number will bwe negative\r<BR>\n" );
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document.write( "t716 = 1000+(716-1)-1.4<BR>\n" );
document.write( "t716 = -1\r<BR>\n" );
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document.write( "-1 is the first negative number.<BR>\n" );
document.write( "S715 will be the sum\r<BR>\n" );
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document.write( "S715 = 715/2[2*1000+714*-1.4]\r<BR>\n" );
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document.write( "S715 = 357643 </SPAN>\n" );
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