document.write( "Question 732377: for the equation of a hyperbola, find the standard equation, vertices, foci, asymptotes, and graph
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document.write( "1) (x^2/36)- (y^2/49)=1\r
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document.write( "2) 25x^2-16y^2-400=0 \n" );
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Algebra.Com's Answer #448069 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! for the equation of a hyperbola, find the standard equation, vertices, foci, asymptotes, and graph \n" ); document.write( "1) (x^2/36)- (y^2/49)=1 \n" ); document.write( "2) 25x^2-16y^2-400=0 \n" ); document.write( "*** \n" ); document.write( "Standard form of equation for a hyperbola with horizontal transverse axis: \n" ); document.write( " \n" ); document.write( ".. \n" ); document.write( "1) (x^2/36)- (y^2/49)=1 \n" ); document.write( "center:(0,0) \n" ); document.write( "a^2=36 \n" ); document.write( "a=√36=6 \n" ); document.write( "vertices: (0±a,0)=(0±6,0)=(6,0) and (-6,0) \n" ); document.write( ".. \n" ); document.write( "b^2=49 \n" ); document.write( "b=√49=7 \n" ); document.write( ".. \n" ); document.write( "c^2=a^2+b^2=36+49=85 \n" ); document.write( "c=√85≈9.2 \n" ); document.write( "foci: (0±c,0)=(0±9.2,0)=(9.2,0) and (-9.2,0) \n" ); document.write( ".. \n" ); document.write( "slopes of asymptotes=±b/a=±7/6 \n" ); document.write( "Equation of asymptote with slope,m=7/6 \n" ); document.write( "y=7x/6 \n" ); document.write( ".. \n" ); document.write( "Equation of asymptote with slope,m=-7/6 \n" ); document.write( "y=-7x/6\r \n" ); document.write( "\n" ); document.write( ".. \n" ); document.write( "see graph below: \n" ); document.write( "y=±(49x^2/36-49)^.5\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I will let you do the 2nd problem. \n" ); document.write( " |